5n^2=70

Solution for 5n^2=70 equation:

5n^2=70

We move all terms to the left:

5n^2-(70)=0

a = 5; b = 0; c = -70;
Δ = b2-4ac
Δ = 02-4·5·(-70)
Δ = 1400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1400}=\sqrt{100*14}=\sqrt{100}*\sqrt{14}=10\sqrt{14}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{14}}{2*5}=\frac{0-10\sqrt{14}}{10}
=-\frac{10\sqrt{14}}{10}
=-\sqrt{14}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{14}}{2*5}=\frac{0+10\sqrt{14}}{10}
=\frac{10\sqrt{14}}{10}
=\sqrt{14}
$